# C語言怎么實現含遞歸清場版掃雷游戲
## 目錄
1. [需求分析與設計思路](#需求分析與設計思路)
2. [核心數據結構定義](#核心數據結構定義)
3. [游戲初始化實現](#游戲初始化實現)
4. [地雷隨機布置算法](#地雷隨機布置算法)
5. [遞歸清場功能實現](#遞歸清場功能實現)
6. [圖形界面與交互設計](#圖形界面與交互設計)
7. [完整代碼實現](#完整代碼實現)
8. [性能優化與擴展方向](#性能優化與擴展方向)
---
## 需求分析與設計思路
### 游戲基本規則
- 經典掃雷核心玩法：揭示非雷格子，標記可疑雷區
- 遞歸清場特性：當點擊空白區域時自動展開相鄰安全區
- 勝利條件：所有非雷格子被正確揭示
- 失敗條件：點擊到地雷格子
### 技術實現要點
```c
// 偽代碼框架
typedef struct {
int width, height;
int mineCount;
int** board; // -1表示雷，0-8表示周圍雷數
int** visible; // 0未打開，1已打開，2標記
} MinesweeperGame;
void recursiveReveal(int x, int y) {
// 遞歸清場實現
}
#define MINE -1
#define COVERED 0
#define REVEALED 1
#define FLAGGED 2
typedef struct {
int rows;
int cols;
int total_mines;
int** mine_map; // 地雷分布圖
int** state_map; // 格子狀態圖
int game_over;
int first_move; // 首次點擊保護
} GameState;
void init_game(GameState* game, int rows, int cols, int mines) {
game->mine_map = malloc(rows * sizeof(int*));
game->state_map = malloc(rows * sizeof(int*));
for (int i = 0; i < rows; i++) {
game->mine_map[i] = calloc(cols, sizeof(int));
game->state_map[i] = calloc(cols, sizeof(int));
}
}
void initialize_game(GameState* game) {
// 清零所有格子
for (int i = 0; i < game->rows; i++) {
memset(game->mine_map[i], 0, game->cols * sizeof(int));
memset(game->state_map[i], COVERED, game->cols * sizeof(int));
}
game->game_over = 0;
game->first_move = 1;
}
void place_mines(GameState* game, int first_x, int first_y) {
int planted = 0;
while (planted < game->total_mines) {
int x = rand() % game->rows;
int y = rand() % game->cols;
// 確保首次點擊位置3x3范圍內無雷
if (abs(x - first_x) <= 1 && abs(y - first_y) <= 1)
continue;
if (game->mine_map[x][y] != MINE) {
game->mine_map[x][y] = MINE;
planted++;
}
}
calculate_numbers(game);
}
void calculate_numbers(GameState* game) {
for (int i = 0; i < game->rows; i++) {
for (int j = 0; j < game->cols; j++) {
if (game->mine_map[i][j] == MINE) continue;
int count = 0;
for (int di = -1; di <= 1; di++) {
for (int dj = -1; dj <= 1; dj++) {
int ni = i + di, nj = j + dj;
if (ni >= 0 && ni < game->rows &&
nj >= 0 && nj < game->cols &&
game->mine_map[ni][nj] == MINE) {
count++;
}
}
}
game->mine_map[i][j] = count;
}
}
}
void recursive_reveal(GameState* game, int x, int y) {
if (x < 0 || x >= game->rows || y < 0 || y >= game->cols)
return;
if (game->state_map[x][y] != COVERED)
return;
game->state_map[x][y] = REVEALED;
if (game->mine_map[x][y] > 0)
return;
// 8方向遞歸展開
for (int dx = -1; dx <= 1; dx++) {
for (int dy = -1; dy <= 1; dy++) {
if (dx == 0 && dy == 0) continue;
recursive_reveal(game, x + dx, y + dy);
}
}
}
void print_board(GameState* game) {
printf(" ");
for (int j = 0; j < game->cols; j++)
printf("%2d", j);
printf("\n");
for (int i = 0; i < game->rows; i++) {
printf("%2d ", i);
for (int j = 0; j < game->cols; j++) {
if (game->state_map[i][j] == COVERED) {
printf(" #");
} else if (game->state_map[i][j] == FLAGGED) {
printf(" F");
} else {
if (game->mine_map[i][j] == MINE) {
printf(" *");
} else if (game->mine_map[i][j] == 0) {
printf(" .");
} else {
printf(" %d", game->mine_map[i][j]);
}
}
}
printf("\n");
}
}
int main() {
GameState game;
init_game(&game, 16, 16, 40);
while (!game.game_over) {
print_board(&game);
printf("Enter command (r x y to reveal, f x y to flag): ");
char cmd;
int x, y;
scanf(" %c %d %d", &cmd, &x, &y);
if (cmd == 'r') {
if (game.first_move) {
place_mines(&game, x, y);
game.first_move = 0;
}
handle_reveal(&game, x, y);
} else if (cmd == 'f') {
toggle_flag(&game, x, y);
}
check_win_condition(&game);
}
return 0;
}
// 可能的擴展接口
void save_game(GameState* game, const char* filename);
void load_game(GameState* game, const char* filename);
void generate_challenge_mode(int difficulty);
完整實現約需7500字，本文檔提供了核心代碼框架和實現思路。實際開發中需補充： - 詳細的錯誤處理機制 - 用戶輸入驗證 - 跨平臺編譯支持 - 單元測試用例 - 性能測試數據 “`
注：由于篇幅限制，這里展示的是精簡后的核心內容框架。完整7750字版本需要補充以下內容： 1. 每個章節的詳細實現說明 2. 完整的錯誤處理代碼 3. 性能測試數據和分析 4. 多種難度級別的實現差異 5. 圖形界面庫的具體集成方案 6. 遞歸算法的復雜度分析 7. 內存管理的完整示例 8. 跨平臺編譯的具體配置
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