今天就跟大家聊聊有關如何判斷鏈表是否包含環,可能很多人都不太了解,為了讓大家更加了解,小編給大家總結了以下內容,希望大家根據這篇文章可以有所收獲。
1 問題
判斷鏈表是否包含環
2 思路
2個指針,一個指針走一步,一個指針走2步,如果相遇則有,反之無。
3 代碼實現
#include <stdio.h>
#include <stdlib.h>
#define true 1
#define false 0;
typedef struct node
{
int value;
struct node *next;
}Node;
/*
*判斷鏈表是否有環
*/
int isCircleList(Node *head)
{
if (head == NULL)
{
return false;
}
Node *first = NULL;
Node *second = NULL;
first = head;
second = head;
while (second != NULL && (second->next) != NULL && (second->next->next != NULL))
{
first = first->next;
second = second->next->next;
if (first == second)
{
return true;
}
}
return false;
}
int main()
{
Node *head = NULL;
Node *node1 = NULL;
Node *node2 = NULL;
Node *node3 = NULL;
Node *node4 = NULL;
Node *node5 = NULL;
Node *node6 = NULL;
Node *node7 = NULL;
head = (Node *)malloc(sizeof(Node));
node1 = (Node *)malloc(sizeof(Node));
node2 = (Node *)malloc(sizeof(Node));
node3 = (Node *)malloc(sizeof(Node));
node4 = (Node *)malloc(sizeof(Node));
node5 = (Node *)malloc(sizeof(Node));
node6 = (Node *)malloc(sizeof(Node));
node7 = (Node *)malloc(sizeof(Node));
if (head == NULL || node1 == NULL || node2 == NULL || node3 == NULL
|| node4 == NULL || node5 == NULL || node6 == NULL || node7 == NULL)
{
printf("malloc fail\n");
return false;
}
// node7<-node6 <-node5
// | |
//head->node1->node2->node3->node4
head->value = 0;
head->next = node1;
node1->value = 1;
node1->next = node2;
node2->value = 2;
node2->next = node3;
node3->value = 3;
node3->next = node4;
node4->value = 4;
node4->next = node5;
node5->value = 5;
node5->next = node6;
node6->value = 6;
node6->next = node7;
node7->value = 7;
node7->next = node2;
int result = isCircleList(head);
if (result)
{
printf("list have circle\n");
}
else
{
printf("list do not have circle\n");
}
return true;
}4 運行結果
list have circle
看完上述內容,你們對如何判斷鏈表是否包含環有進一步的了解嗎?如果還想了解更多知識或者相關內容,請關注億速云行業資訊頻道,感謝大家的支持。
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