井字棋,英文名叫Tic-Tac-Toe,是一種在3*3格子上進行的連珠游戲,和五子棋類似,由于棋盤一般不畫邊框,格線排成井字故得名。游戲需要的工具僅為紙和筆,然后由分別代表O和X的兩個游戲者輪流在格子里留下標記(一般來說先手者為X),任意三個標記形成一條直線,則為獲勝。
游戲的難點在于,如何判斷連接成了一條線;橫、豎、斜三個方向;
游戲的代碼:
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
u'''
Created on 2019年4月13日
@author: wuluo
'''
__author__ = 'wuluo'
__version__ = '1.0.0'
__company__ = u'重慶交大'
__updated__ = '2019-04-13'
# 創建井字棋的程序
def initBoard():
global board # 調用全局的board
board = [None] * 3
print("井字棋:")
for i in range(len(board)):
board[i] = ["+ "] * 3
# 打印井字棋的程序
def printBoard():
global board
for i in range(len(board)):
for j in range(len(board[i])):
print(board[i][j], end=" ")
print("")
# 開始下棋的程序
def startGame():
global board
player = 0
while isGameContinue():
if player <= 8:
if player % 2 == 0:
# 甲方下棋
print("==>黑方下棋")
if not playChess("x"):
continue
else:
# 乙方下棋
print("==>白方下棋")
if not playChess("○"):
continue
player += 1
else:
print("平局")
break
def playChess(chess):
# 獲取位置
x = int(input("==> X=")) - 1
y = int(input("==> Y=")) - 1
if board[x][y] == "+ ":
board[x][y] = chess
printBoard()
return True # 落子成功
else:
print("==> 已有棋子 請重新落子\a")
printBoard()
return False # 落子失敗
def isGameContinue():
for i in range(len(board)):
for j in range(len(board[i])):
if board[i][j] != "+ ":
# 橫向
if j == 0:
if board[i][j] == board[i][j + 1] == board[i][j + 2]:
whoWin(i, j)
return False
# 豎向
if i == 0:
if board[i][j] == board[i + 1][j] == board[i + 2][j]:
whoWin(i, j)
return False
# 正斜
if i == 0 and j == 0:
if board[i][j] == board[i + 1][j + 1] == board[i + 2][j + 2]:
whoWin(i, j)
return False
# 反斜
if i == 2 and j == 0:
if board[i][j] == board[i - 1][j + 1] == board[i - 2][j + 2]:
whoWin(i, j)
return False
return True
def whoWin(i, j):
if board[i][j] == "x":
print("黑方勝!")
else:
print("白方勝!")
for i in range(3):
print("win")
class main():
board = []
initBoard()
printBoard()
startGame()
if __name__ == "__main__":
main()
游戲結果:


還有一種結果是平局:

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